Find the 3 largest elements in the Array
Simple Approach will update soon with the newly learnt approach. :)
let arr = [1,2,3,3,4,5,4,6,7,7,7,8,9,10,10,10,10]
let n = arr.length
function thirdLargest (arr,n){
let first, second , third ;
second = first = third = Number.MIN_VALUE
if(n<3)
{ console.log("Invaild on the given array") }
else
{ console.log("let's rock n roll")}
for (let i = 0; i<=n ; i++ )
if (arr[i] > first){
third = second
second = first
first = arr[i]
}
else if (arr[i] > second && arr[i] != first){
third = second
second = arr[i]
}
else if(arr[i] > third && arr[i] != second){
first = arr[i]
}
console.log(first,second,third) }
thirdLargest(arr,n)
